x^'=8x+3

Lösung

x^{^{'}} = 8 x + 3

x = \frac{e ^{8 t + c_{1}}}{8} - \frac{3}{8}

Schritte zur Lösung

x^{'} (t) = 8 x + 3

Solve separable ODE:

x = \frac{e ^{8 t + c_{1}}}{8} - \frac{3}{8}

x = \frac{e ^{8 t + c_{1}}}{8} - \frac{3}{8}

\frac{d y}{d t} = k y, y (0) = y

\frac{d y}{d x} = - \frac{y ^{2}}{e}

(x + x^{2}) y^{^{'}} y = y^{2} - 2

2 x y + x^{2} y^{^{'}} = 0

P^{^{'}} = 0.6 \cdot P \cdot (1 - \frac{P}{840})