y^'=(1-y^2)^{0.5}

Lösung

y^{^{'}} = (1 - y^{2})^{0.5}

y = sin (t + c_{1})

Schritte zur Lösung

y^{'} (t) = (1 - y^{2})^{0.5}

Solve separable ODE:

y = sin (t + c_{1})

y = sin (t + c_{1})

y^{^{'}} = y^{2} (t)

\frac{d y}{d x} x = \frac{2}{3} (y - 1)^{\frac{3}{2}}

(x - 13) (x - 3) y^{^{'}} = y

x d y - (y + 4) d x = 0

\frac{d y}{d x} = 14 e^{5 x - y}, y (0) = 0