(x-2)y^'-y+1=0

Lösung

(x - 2) y^{^{'}} - y + 1 = 0

y = e^{c_{1}} x - 2 e^{c_{1}} + 1

Schritte zur Lösung

(x - 2) y^{'} (x) - y + 1 = 0

Solve separable ODE:

y = e^{c_{1}} x - 2 e^{c_{1}} + 1

y = e^{c_{1}} x - 2 e^{c_{1}} + 1

a y^{^{'}} = - b y^{2} - c, y (0) = 10

(u - 1) d x + (x + ux) d u = 0

2 t (\frac{d y}{d t}) = 6 y

\frac{d}{d x} (y^{2}) = x^{2}

\frac{d y}{d x} 2 x y = 1