derivative of sin^2(cos(4x))

Lösung

\frac{d}{d x} (sin^{2} (cos (4 x)))

- 8 sin (cos (4 x)) cos (cos (4 x)) sin (4 x)

Schritte zur Lösung

\frac{d}{d x} (sin^{2} (cos (4 x)))

Wende die Kettenregel an:

2 sin (cos (4 x)) \frac{d}{d x} (sin (cos (4 x)))

= 2 sin (cos (4 x)) \frac{d}{d x} (sin (cos (4 x)))

\frac{d}{d x} (sin (cos (4 x))) = - 4 cos (cos (4 x)) sin (4 x)

= 2 sin (cos (4 x)) (- 4 cos (cos (4 x)) sin (4 x))

Vereinfache

= - 8 sin (cos (4 x)) cos (cos (4 x)) sin (4 x)

\frac{d y}{d x} = 13 x + y - 13

\int_{0}^{π} x^{2} cos (x) d x

\int \frac{4 x ^{2} + 13 x - 9}{x ^{3} + 2 x ^{2} - 3 x} d x

\frac{d y}{d t} + 3 y = cos (2 t), y (0) = - 1

\int \frac{a + b sin ^{3} ( t )}{cos ^{2} ( t )} d t