y^'sec(x)=5y^2,y((9pi)/2)= 1/6

Lösung

y^{^{'}} sec (x) = 5 y^{2}, y (\frac{9 π}{2}) = \frac{1}{6}

y = - \frac{1}{5 sin ( x ) - 11}

Schritte zur Lösung

y^{'} (x) sec (x) = 5 y^{2}

Solve separable ODE:

y = - \frac{1}{5 sin ( x ) - 11}

y = - \frac{1}{5 sin ( x ) - 11}

\frac{d y}{d x} = \frac{3}{y ^{2}}

\frac{d y}{d x} y = - \frac{2}{3 x ^{4}}

\frac{d N}{d t} - 254 N = 0

x^{^{'}} = - 5 x^{2}

y = e^{- x} \cdot sin (2 x) \cdot \frac{d y}{d x}