y^'tan(x)-y=0

Lösung

y^{^{'}} tan (x) - y = 0

y = c_{1} sin (x)

Schritte zur Lösung

y^{'} (x) tan (x) - y = 0

Solve separable ODE:

y = c_{1} sin (x)

y = c_{1} sin (x)

- 4 y^{^{'}} = 1 + x + y + x y

(8 + y) y^{^{'}} = sin (6 + x)

\frac{d x}{d t} = 14 - 0.56 x, t (0) = 130

d x = \frac{1}{1 + y ^{2}} d y

x - \frac{y}{y ^{^{'}}} = 2 x - 3 x^{2}