y^'= y/(81t^2+1)

Lösung

y^{^{'}} = \frac{y}{81 t ^{2} + 1}

y = e^{\frac{1}{9} a r c t a n (9 t) + c_{1}}

Schritte zur Lösung

y^{'} (t) = \frac{y}{81 t ^{2} + 1}

Solve separable ODE:

y = e^{\frac{1}{9} a r c t a n (9 t) + c_{1}}

y = e^{\frac{1}{9} a r c t a n (9 t) + c_{1}}

y^{^{'}} = - 2 t y^{2}, y (0) = 1

\frac{d N}{d t} + N = Nt (e^{t + 2})

\frac{y ^{^{'}}}{y} = \frac{4}{x}

\frac{d y}{d x} = (\frac{3 x - 5}{y - 2})

\frac{d y}{d t} = - y + 1