y^'=ab-y/c b

Lösung

y^{^{'}} = ab - \frac{y}{c} b

y = - \frac{e ^{\frac{- b t - c _{1} b}{c}}}{b} + c a

Schritte zur Lösung

y^{'} (t) = ab - \frac{y}{c} b

Solve separable ODE:

y = - \frac{e ^{\frac{- b t - c _{1} b}{c}}}{b} + c a

y = - \frac{e ^{\frac{- b t - c _{1} b}{c}}}{b} + c a

\frac{d y}{d x} = \frac{x x ^{2} + 3}{e ^{2 y}}

y^{^{'}} = 6 x y - 2 x

3 x + 2 y^{2} d x + 2 x y d y = 0

\frac{d y}{d x} = x^{3} (y - 2), y (0) = 4

y^{^{'}} = y cos (x), y (0) = 5