(1+x^2)*y^'=x(1-y)

Lösung

(1 + x^{2}) \cdot y^{^{'}} = x (1 - y)

y = - \frac{c _{1}}{1 + x ^{2}} + 1

Schritte zur Lösung

(1 + x^{2}) \cdot y^{'} (x) = x (1 - y)

Solve separable ODE:

y = - \frac{c _{1}}{1 + x ^{2}} + 1

y = - \frac{c _{1}}{1 + x ^{2}} + 1

\frac{d y}{d x} - 2 x y = 4 x, y (0) = 3

\frac{d y}{d x} = y \cdot sin (x)

y (x^{3} d y + y^{3} d x) = 0

\frac{d t}{d x} = \frac{( 3000 - x )}{100}

3 x^{^{'}} + 21 x = 0