xy^'*y=x^2sin(x)

Lösung

x y^{^{'}} \cdot y = x^{2} sin (x)

y = - 2 x cos (x) + 2 sin (x) + c_{1}, y = - - 2 x cos (x) + 2 sin (x) + c_{1}

Schritte zur Lösung

x y^{'} (x) \cdot y = x^{2} sin (x)

Solve separable ODE:

y = - 2 x cos (x) + 2 sin (x) + c_{1}, y = - - 2 x cos (x) + 2 sin (x) + c_{1}

y = - 2 x cos (x) + 2 sin (x) + c_{1}, y = - - 2 x cos (x) + 2 sin (x) + c_{1}

\frac{d v}{d t} = - 0.004 v^{2}

x sin (y) d x + cos (y) (1 + x^{2}) d y = 0

\frac{d z}{d t} + 9 e^{8 t + 4 z} = 0

\frac{d V}{d t} = 50 - \frac{7 V}{100}

7 y^{^{'}} + y = 0