sqrt((1+cos(2x))/(1+sin(y)))+y^'=0

Lösung

\frac{1 + cos ( 2 x )}{1 + sin ( y )} + y^{^{'}} = 0

y = 2 arcsin (\frac{- 2 sin ( x ) + c _{1}}{2 2}) + 4 πn + \frac{π}{2}, y = 2 π + 2 arcsin (- \frac{- 2 sin ( x ) + c _{1}}{2 2}) + 4 πn + \frac{π}{2}

Schritte zur Lösung

\frac{1 + cos ( 2 x )}{1 + sin ( y )} + y^{'} (x) = 0

Solve separable ODE:

y = 2 arcsin (\frac{- 2 sin ( x ) + c _{1}}{2 2}) + 4 πn + \frac{π}{2}, y = 2 π + 2 arcsin (- \frac{- 2 sin ( x ) + c _{1}}{2 2}) + 4 πn + \frac{π}{2}

y = 2 arcsin (\frac{- 2 sin ( x ) + c _{1}}{2 2}) + 4 πn + \frac{π}{2}, y = 2 π + 2 arcsin (- \frac{- 2 sin ( x ) + c _{1}}{2 2}) + 4 πn + \frac{π}{2}

e^{- x} sin (y) \frac{d y}{d x} = 1 + e^{- x}

\frac{df}{d x} = 2 f (x) tan (x)

\frac{d y}{d x} - x y = 3 x

\frac{d y}{d x} = \frac{3 y ^{2} - x y ^{2}}{x ^{2} y + 5 x ^{2}}

(2 x y - 3 y) d x + (x^{2} - 3 x) d y = 0