xy^'cos(y)+sin(y)=0

Lösung

x y^{^{'}} cos (y) + sin (y) = 0

y = arcsin (\frac{c _{1}}{x}) + 2 πn, y = π + arcsin (- \frac{c _{1}}{x}) + 2 πn

Schritte zur Lösung

x y^{'} (x) cos (y) + sin (y) = 0

Solve separable ODE:

y = arcsin (\frac{c _{1}}{x}) + 2 πn, y = π + arcsin (- \frac{c _{1}}{x}) + 2 πn

y = arcsin (\frac{c _{1}}{x}) + 2 πn, y = π + arcsin (- \frac{c _{1}}{x}) + 2 πn

(1 + x^{2}) y^{^{'}} - 2 x (y + 3) = 0

\frac{d y}{d x} = y + 7

\frac{d x}{d t} = 14 - 0.28 \cdot x

\frac{d y}{d t} = \frac{3 t ^{2}}{8 y}

y^{^{'}} = (8 x - 5) (y + 2)