2x^2y+3xy^'-(2x^2-1)y=0

Lösung

2 x^{2} y + 3 x y^{^{'}} - (2 x^{2} - 1) y = 0

y = \frac{c _{1}}{3 x}

Schritte zur Lösung

2 x^{2} y + 3 x y^{'} (x) - (2 x^{2} - 1) y = 0

Solve separable ODE:

y = \frac{c _{1}}{3 x}

y = \frac{c _{1}}{3 x}

x^{2} y^{2} + 3 x y^{^{'}} = 0

y^{2} \frac{d y}{d x} = 3 x^{2}

x^{^{'}} = k x + 5

y^{^{'}} - y + 2 y^{2} = 0, y (0) = 1

(y x^{2} - 7 y - x^{2} + 7) d x + d y = 0