(dv)/(dt)=10+2v

Lösung

\frac{d v}{d t} = 10 + 2 v

v = e^{2 t + c_{1}} - 5

Schritte zur Lösung

\frac{d v}{d t} = 10 + 2 v

Solve separable ODE:

v = e^{2 t + c_{1}} - 5

v = e^{2 t + c_{1}} - 5

y^{^{'}} = y^{- 9} x^{9}, y (0) = 9

\frac{d y}{d x} = - 12 x^{3} y

y^{^{'}} = b \cdot y + c

(x tan (x)) d x - (y cos (x)) d y = 0

x^{^{'}} - a \cdot x = 0