y^'=(e^y)/(cos^2(t))

Lösung

y^{^{'}} = \frac{e ^{y}}{cos ^{2} ( t )}

y = - ln (- tan (t) - c_{1})

Schritte zur Lösung

y^{'} (t) = \frac{e ^{y}}{cos ^{2} ( t )}

Solve separable ODE:

y = - ln (- tan (t) - c_{1})

y = - ln (- tan (t) - c_{1})

\frac{d y}{d x} = a y + b

\frac{1}{x} d x = \frac{1}{y} d y

x y^{2} y^{^{'}} = ln (x)

V^{^{'}} - V^{2} = 5

\frac{d y}{d x} = - 5 y