y^'+50y=5,y(0)=0,y(0)=0

Lösung

y^{^{'}} + 50 y = 5, y (0) = 0, y (0) = 0

y = - \frac{e ^{- 50 t}}{10} + \frac{1}{10}

Schritte zur Lösung

y^{'} (t) + 50 y = 5

Solve separable ODE:

y = - \frac{e ^{- 50 t}}{10} + \frac{1}{10}

y = - \frac{e ^{- 50 t}}{10} + \frac{1}{10}

(x + 3) d y = \frac{1}{y ^{2}} d x

y^{^{'}} + x y = 0, y (0) = 2

10 - 100 x = \frac{20 d x}{d t}

y^{^{'}} + \frac{12}{280} y = 3

ln (y) d y = x y sin (x) d x