ydx+(x^2-x)dy=0

Lösung

y d x + (x^{2} - x) d y = 0

y = \frac{c _{1} x}{x - 1}

Schritte zur Lösung

y d x + (x^{2} - x) d y = 0

Solve separable ODE:

y = \frac{c _{1} x}{x - 1}

y = \frac{c _{1} x}{x - 1}

y^{^{'}} = 3 y^{- 2}

h^{^{'}} = x ln (x) 2 h

\frac{d y}{d x} = 56 y x^{7}

\frac{d y}{d x} = \frac{x ( y + 2 ) ^{2}}{e ^{- x^{2}}}

\frac{d y}{d x} 4 y^{2} = \frac{3 x - 15}{3 x + 15}