y^{''}+y=16cos(3x)

Lösung

y^{^{''}} + y = 16 cos (3 x)

y = c_{1} cos (x) + c_{2} sin (x) - 2 cos (3 x)

Schritte zur Lösung

y^{''} (x) + y = 16 cos (3 x)

Solve linear ODE:

y = c_{1} cos (x) + c_{2} sin (x) - 2 cos (3 x)

y = c_{1} cos (x) + c_{2} sin (x) - 2 cos (3 x)

\frac{d ^{2} y}{d x ^{2}} + 2 \frac{d y}{d x} + 5 y = e^{- x}

y^{^{''}} + 2 y^{^{'}} + 5 y = 4 e^{(- x)} cos (2 x)

y^{^{''}} + 6 y^{^{'}} + 9 y = \frac{8 e ^{- 3 x}}{x ^{2} + 1}

y^{^{'''}} + 2 y^{^{''}} = 32 e^{2 x} + 24 x

y^{^{''}} - 4 y^{^{'}} + 3 y = 4 e^{3 x}