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Beliebt Rechnen >

y^{''}-y^'=te^t,y(0)=2,y^'(0)=1

Lösung

y^{^{''}} - y^{^{'}} = t e^{t}, y (0) = 2, y^{^{'}} (0) = 1

Lösung

y = \frac{e ^{t} t ^{2}}{2} - e^{t} t + 2 e^{t}

Schritte zur Lösung

y^{''} (t) - y^{'} (t) = t e^{t}

Solve linear ODE:

y = \frac{e ^{t} t ^{2}}{2} - e^{t} t + 2 e^{t}

y = \frac{e ^{t} t ^{2}}{2} - e^{t} t + 2 e^{t}

Graph

Beliebte Beispiele

y^{''}+3y^'+2y=e^t

y^{^{''}} + 3 y^{^{'}} + 2 y = e^{t}

y^{''}+4y=-12sin(2x)

y^{^{''}} + 4 y = - 12 sin (2 x)

y^{'''}-4y^{''}=x+xe^{4x}

y^{^{'''}} - 4 y^{^{''}} = x + x e^{4 x}

y^{'''}-y^{''}+y^'-y=xe^x-e^{-x}+7

y^{^{'''}} - y^{^{''}} + y^{^{'}} - y = x e^{x} - e^{- x} + 7

y^{''}+36y=csc(6x)

y^{^{''}} + 36 y = csc (6 x)