What is the solution for (4d^2-4d+1)y=100 ?

The solution for (4d^2-4d+1)y=100 is y=c_{1}e^{x/2}+c_{2}e^{x/2}x+100

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(4d^2-4d+1)y=100

(4 d^{2} - 4 d + 1) y = 100

y = c_{1} e^{\frac{x}{2}} + c_{2} e^{\frac{x}{2}} x + 100

Solution steps

(4 d^{2} - 4 d + 1) y = 100

Solve linear ODE:

y = c_{1} e^{\frac{x}{2}} + c_{2} e^{\frac{x}{2}} x + 100

y = c_{1} e^{\frac{x}{2}} + c_{2} e^{\frac{x}{2}} x + 100

What is the solution for (4d^2-4d+1)y=100 ?
The solution for (4d^2-4d+1)y=100 is y=c_{1}e^{x/2}+c_{2}e^{x/2}x+100