y^{''}+9y=2,y(0)=0,y^'(0)=0

Lösung

y^{^{''}} + 9 y = 2, y (0) = 0, y^{^{'}} (0) = 0

y = - \frac{2}{9} cos (3 t) + \frac{2}{9}

Schritte zur Lösung

y^{''} (t) + 9 y = 2

Solve linear ODE:

y = - \frac{2}{9} cos (3 t) + \frac{2}{9}

y = - \frac{2}{9} cos (3 t) + \frac{2}{9}

y^{^{''}} + 2 y^{^{'}} + y = t

y^{^{''}} + y = cos (x) + sec (x)

y^{^{''}} - 5 y^{^{'}} + 6 y = 2 e^{- x}

y^{^{''}} - 2 y^{^{'}} + y = 13 e^{x}

y^{^{''}} - y^{^{'}} = e^{x} + 1