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Beliebt Rechnen >

y^{''}+4y=2,y(0)=0,y^'(0)=0

Lösung

y^{^{''}} + 4 y = 2, y (0) = 0, y^{^{'}} (0) = 0

Lösung

y = - \frac{1}{2} cos (2 t) + \frac{1}{2}

Schritte zur Lösung

y^{''} (t) + 4 y = 2

Solve linear ODE:

y = - \frac{1}{2} cos (2 t) + \frac{1}{2}

y = - \frac{1}{2} cos (2 t) + \frac{1}{2}

Graph

Beliebte Beispiele

y^{''}-2y^'+2y=e^2x(cos(x)-5sin(x))

y^{^{''}} - 2 y^{^{'}} + 2 y = e^{2} x (cos (x) - 5 sin (x))

y^{''}-y^'+1/4 y=xe^{x/2}

y^{^{''}} - y^{^{'}} + \frac{1}{4} y = x e^{\frac{x}{2}}

4 x^{^{''}} - 2 x = 7

y^{''}+4y^'+4=(e^{-2x})/(x^3)

y^{^{''}} + 4 y^{^{'}} + 4 = \frac{e ^{- 2 x}}{x ^{3}}

y^{''}-y=3sin(2x)

y^{^{''}} - y = 3 sin (2 x)