What is the solution for f^'(x)=sqrt(1-2x) ?

The solution for f^'(x)=sqrt(1-2x) is f(x)=-1/3 (1-2x)^{3/2}+c_{1}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

f^'(x)=sqrt(1-2x)

f^{^{'}} (x) = 1 - 2 x

f (x) = - \frac{1}{3} (1 - 2 x)^{\frac{3}{2}} + c_{1}

Solution steps

f^{'} (x) = 1 - 2 x

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

f (x) = \int 1 - 2 x d x

\int 1 - 2 x d x = - \frac{1}{3} (1 - 2 x)^{\frac{3}{2}} + c_{1}

f (x) = - \frac{1}{3} (1 - 2 x)^{\frac{3}{2}} + c_{1}

What is the solution for f^'(x)=sqrt(1-2x) ?
The solution for f^'(x)=sqrt(1-2x) is f(x)=-1/3 (1-2x)^{3/2}+c_{1}