y^{''}+y=sinh(2x)

Lösung

y^{^{''}} + y = sinh (2 x)

y = c_{1} cos (x) + c_{2} sin (x) + \frac{cos ( x ) ( cos ( x ) sinh ( 2 x ) - 2 sin ( x ) cosh ( 2 x ) )}{5} + sin (x) \cdot \int cos (x) sinh (2 x) d x

Schritte zur Lösung

y^{''} (x) + y = sinh (2 x)

Solve linear ODE:

y = c_{1} cos (x) + c_{2} sin (x) + \frac{cos ( x ) ( cos ( x ) sinh ( 2 x ) - 2 sin ( x ) cosh ( 2 x ) )}{5} + sin (x) \cdot \int cos (x) sinh (2 x) d x

y = c_{1} cos (x) + c_{2} sin (x) + \frac{cos ( x ) ( cos ( x ) sinh ( 2 x ) - 2 sin ( x ) cosh ( 2 x ) )}{5} + sin (x) \cdot \int cos (x) sinh (2 x) d x

y^{^{''}} + y^{^{'}} + 9.25 = 0

x^{^{''}} + 49 x = 65 cos (6 t)

y^{^{''}} - 3 y^{^{'}} + 2 y = 2 e^{3 x} + e^{- x}

y^{^{''}} - 2 y^{^{'}} + y = 4 e^{x}

y^{^{''}} + y^{^{'}} = n