y^{''}-2y^'=4

Lösung

y^{^{''}} - 2 y^{^{'}} = 4

y = c_{1} e^{2 t} + c_{2} - 2 t

Schritte zur Lösung

y^{''} (t) - 2 y^{'} (t) = 4

Solve linear ODE:

y = c_{1} e^{2 t} + c_{2} - 2 t

y = c_{1} e^{2 t} + c_{2} - 2 t

y^{^{''}} + 4 y^{^{'}} + 3 y = e^{3 x}

so l v e f or d, d (p) = 480 - 3 p

y^{^{''}} + 4 y = 3 \cdot sin (2 x)

y^{^{''}} - y = 5 x + 2

\frac{d ^{3} y}{d x ^{3}} + y = cos (x)