D(t)=t+5

解答

D (t) = t + 5

t = \frac{5}{D - 1}; D \neq = 1

求解步骤

D (t) = t + 5

展开

D (t) : D t

D t = t + 5

将

t

para o lado esquerdo

D t - t = 5

分解

D t - t : t (D - 1)

t (D - 1) = 5

两边除以

D - 1; D \neq = 1

t = \frac{5}{D - 1}; D \neq = 1

y^{^{''}} + 2 y^{^{'}} - y = t^{- 1} e^{t}

y^{^{''}} - 2 y^{^{'}} + 2 y = sin (t), y (0) = 0, y^{^{'}} (0) = 1

y^{^{''}} - 5 y^{^{'}} + 6 y = 3 x^{2} + 5 x

y^{^{''}} + 2 y^{^{'}} - 3 y = 5 e^{2 x}, y (0) = 0, y^{^{'}} (0) = a

y^{^{''}} + 4 y = sin^{22} (x)