What is the tangent of y^2+5x=x^2y-5,(3,5) ?

The tangent of y^2+5x=x^2y-5,(3,5) is y=25x-70

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

tangent of y^2+5x=x^2y-5,(3,5)

tangent of

y^{2} + 5 x = x^{2} y - 5, (3, 5)

y = 25 x - 70

Solution steps

Find the slope of

y^{2} + 5 x = x^{2} y - 5 : \frac{d y}{d x} = \frac{2 x y - 5}{2 y - x ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 25

Find the line with slope m=

25

and passing through

(3, 5) : y = 25 x - 70

y = 25 x - 70

What is the tangent of y^2+5x=x^2y-5,(3,5) ?
The tangent of y^2+5x=x^2y-5,(3,5) is y=25x-70