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Beliebt Rechnen >

y^{''}+y=2sin(2t),y(0)=12,y^'(0)=0

Lösung

y^{^{''}} + y = 2 sin (2 t), y (0) = 12, y^{^{'}} (0) = 0

Lösung

y = 12 cos (t) + \frac{4}{3} sin (t) - \frac{2}{3} sin (2 t)

Schritte zur Lösung

y^{''} (t) + y = 2 sin (2 t)

Solve linear ODE:

y = 12 cos (t) + \frac{4}{3} sin (t) - \frac{2}{3} sin (2 t)

y = 12 cos (t) + \frac{4}{3} sin (t) - \frac{2}{3} sin (2 t)

Graph

Beliebte Beispiele

10y^{''}+90y^'+1/(0.05)y=500sin(x)

10 y^{^{''}} + 90 y^{^{'}} + \frac{1}{0.05} y = 500 sin (x)

y^{''}+4x^2+4y=-6

y^{^{''}} + 4 x^{2} + 4 y = - 6

y^{''}+3y^'-1=2x^2+x

y^{^{''}} + 3 y^{^{'}} - 1 = 2 x^{2} + x

y^{''}-4y=24cos(2t)

y^{^{''}} - 4 y = 24 cos (2 t)

y^{''}+2y^'+10y=2cos(x)+cos(3x)

y^{^{''}} + 2 y^{^{'}} + 10 y = 2 cos (x) + cos (3 x)