4q^{''}+8q^'+1/(0.0125)q=88t

Lösung

4 q^{^{''}} + 8 q^{^{'}} + \frac{1}{0.0125} q = 88 t

q (t) = e^{- t} (c_{1} cos (19 t) + c_{2} sin (19 t)) + \frac{11 t}{10} - \frac{11}{100}

Schritte zur Lösung

4 q^{''} (t) + 8 q^{'} (t) + \frac{1}{0.0125} q (t) = 88 t

Solve linear ODE:

q (t) = e^{- t} (c_{1} cos (19 t) + c_{2} sin (19 t)) + \frac{11 t}{10} - \frac{11}{100}

q (t) = e^{- t} (c_{1} cos (19 t) + c_{2} sin (19 t)) + \frac{11 t}{10} - \frac{11}{100}

x^{^{''}} + x^{^{'}} + 2 x = cos (2 t)

\frac{d ^{2} y}{d x ^{2}} - 16 y = 9.6 e^{4 x} + 30 e^{x}

y^{^{'''}} = 3 y^{^{''}} + 9 (e^{2 x}) + 5 (cos (x))

y^{^{''}} + 7 y^{^{'}} + 10 y = 7 u

y^{^{''}} + 4 y = cos (x), y (0) = 0, y^{^{'}} (0) = 0