y^{''}+25y^'=-24e^{-t}

Lösung

y^{^{''}} + 25 y^{^{'}} = - 24 e^{- t}

y = c_{1} + c_{2} e^{- 25 t} + e^{- t}

Schritte zur Lösung

y^{''} (t) + 25 y^{'} (t) = - 24 e^{- t}

Solve linear ODE:

y = c_{1} + c_{2} e^{- 25 t} + e^{- t}

y = c_{1} + c_{2} e^{- 25 t} + e^{- t}

y^{^{''}} + 4 y^{^{'}} + 4 y = sin (x), y (0) = 1, y^{^{'}} (0) = 0

y^{^{''}} + y - 2 e^{- t} - 1 = 0

\frac{d ^{2}}{d x ^{2}} (θ (x)) + 4 θ (x) = csc^{2} (2 x)

(D^{4} + D^{2}) y = 3 x^{2} + 4 sin (x) - 2 cos (x)

y^{^{''}} + 2 y = - 18 x e^{2 x}