What is (\partial)/(\partial x)(sin(kx)) ?

The answer to (\partial)/(\partial x)(sin(kx)) is cos(kx)k

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(\partial)/(\partial x)(sin(kx))

\frac{\partial}{\partial x} (sin (k x))

cos (k x) k

Solution steps

\frac{\partial}{\partial x} (sin (k x))

Apply the chain rule:

cos (k x) \frac{\partial}{\partial x} (k x)

= cos (k x) \frac{\partial}{\partial x} (k x)

\frac{\partial}{\partial x} (k x) = k

= cos (k x) k

What is (\partial)/(\partial x)(sin(kx)) ?
The answer to (\partial)/(\partial x)(sin(kx)) is cos(kx)k