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Beliebt Rechnen >

y^{''}+4y^'+5y=15t

Lösung

y^{^{''}} + 4 y^{^{'}} + 5 y = 15 t

Lösung

y = e^{- 2 t} (c_{1} cos (t) + c_{2} sin (t)) + 3 t - \frac{12}{5}

Schritte zur Lösung

y^{''} (t) + 4 y^{'} (t) + 5 y = 15 t

Solve linear ODE:

y = e^{- 2 t} (c_{1} cos (t) + c_{2} sin (t)) + 3 t - \frac{12}{5}

y = e^{- 2 t} (c_{1} cos (t) + c_{2} sin (t)) + 3 t - \frac{12}{5}

Graph

Beliebte Beispiele

y^{''}-y^'=5sin(2t),y(0)=0,y^'(0)=1

y^{^{''}} - y^{^{'}} = 5 sin (2 t), y (0) = 0, y^{^{'}} (0) = 1

(d^2y)/(dx^2)+9y=sin(3x)sec^2(3x)

\frac{d ^{2} y}{d x ^{2}} + 9 y = sin (3 x) sec^{2} (3 x)

y^{''}+5y^'+6y=sin(t)-cos(2t)

y^{^{''}} + 5 y^{^{'}} + 6 y = sin (t) - cos (2 t)

y^{''}+7y^'+6y=e^{2t}

y^{^{''}} + 7 y^{^{'}} + 6 y = e^{2 t}

y^{''}+4y^'+4y=2e^{-t}

y^{^{''}} + 4 y^{^{'}} + 4 y = 2 e^{- t}