y^{''}-4y^'+5y=10x-3

Lösung

y^{^{''}} - 4 y^{^{'}} + 5 y = 10 x - 3

y = e^{2 x} (c_{1} cos (x) + c_{2} sin (x)) + 2 x + 1

Schritte zur Lösung

y^{''} (x) - 4 y^{'} (x) + 5 y = 10 x - 3

Solve linear ODE:

y = e^{2 x} (c_{1} cos (x) + c_{2} sin (x)) + 2 x + 1

y = e^{2 x} (c_{1} cos (x) + c_{2} sin (x)) + 2 x + 1

y^{^{''}} - 6 y^{^{'}} + 8 y = x e^{x}

- y^{^{''}} - 4 y = t^{2}

y^{^{''}} + 6 y^{^{'}} + 73 y = 8 cos (4 x)

d (x) = x^{2} + 2 x - 25

y^{^{''}} + y^{^{'}} + y = cos (2 t)