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Beliebt Rechnen >

y^{''}+y^'=-cos(2x)

Lösung

y^{^{''}} + y^{^{'}} = - cos (2 x)

Lösung

y = c_{1} + c_{2} e^{- x} - \frac{1}{10} sin (2 x) + \frac{1}{5} cos (2 x)

Schritte zur Lösung

y^{''} (x) + y^{'} (x) = - cos (2 x)

Solve linear ODE:

y = c_{1} + c_{2} e^{- x} - \frac{1}{10} sin (2 x) + \frac{1}{5} cos (2 x)

y = c_{1} + c_{2} e^{- x} - \frac{1}{10} sin (2 x) + \frac{1}{5} cos (2 x)

Graph

Beliebte Beispiele

y^{''}-3y^'+5=e^{2x}-3cos(3x)

y^{^{''}} - 3 y^{^{'}} + 5 = e^{2 x} - 3 cos (3 x)

(D^2+D)(y)=sin(x)

(D^{2} + D) (y) = sin (x)

4y^{''}-y^'+6=0

4 y^{^{''}} - y^{^{'}} + 6 = 0

y^{^{''}} + 4 y = 2 e^{t}

(d^2y)/(dx^2)+2(dy)/(dx)+2*y=2

\frac{d ^{2} y}{d x ^{2}} + 2 \frac{d y}{d x} + 2 \cdot y = 2