ja

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

人気のある微分積分 >

線形 y^{'''}+y^'=sec(x)

解

線形

y^{^{'''}} + y^{^{'}} = sec (x)

解

y = c_{1} + c_{2} cos (x) + c_{3} sin (x) + ln (tan (x) + sec (x)) - x cos (x) + ln (cos (x)) sin (x)

解答ステップ

y^{'''} (x) + y^{'} (x) = sec (x)

線形 ODE を解く:

y = c_{1} + c_{2} cos (x) + c_{3} sin (x) + ln (tan (x) + sec (x)) - x cos (x) + ln (cos (x)) sin (x)

y = c_{1} + c_{2} cos (x) + c_{3} sin (x) + ln (tan (x) + sec (x)) - x cos (x) + ln (cos (x)) sin (x)

グラフ

人気の例

y^{'''}-11y^{''}+35y^'-25=0

y^{^{'''}} - 11 y^{^{''}} + 35 y^{^{'}} - 25 = 0

(d^2y)/(dt^2)+2y=cos(7t)

\frac{d ^{2} y}{d t ^{2}} + 2 y = cos (7 t)

y^{^{''}} + 3 y = 2

y^{''}-2y^'-3y=1,y(0)=0,y^'(0)=0

y^{^{''}} - 2 y^{^{'}} - 3 y = 1, y (0) = 0, y^{^{'}} (0) = 0

a^2*y+y^{''}=cos(b*t),y(0)=0,y^'(0)=0

a^{2} \cdot y + y^{^{''}} = cos (b \cdot t), y (0) = 0, y^{^{'}} (0) = 0