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Beliebt Rechnen >

2y^{''}+y^'+1=2e^2x

Lösung

2 y^{^{''}} + y^{^{'}} + 1 = 2 e^{2} x

Lösung

y = c_{1} + c_{2} e^{- \frac{x}{2}} + e^{2} x^{2} + (- 1 - 4 e^{2}) x

Schritte zur Lösung

2 y^{''} (x) + y^{'} (x) + 1 = 2 e^{2} x

Solve linear ODE:

y = c_{1} + c_{2} e^{- \frac{x}{2}} + e^{2} x^{2} + (- 1 - 4 e^{2}) x

y = c_{1} + c_{2} e^{- \frac{x}{2}} + e^{2} x^{2} + (- 1 - 4 e^{2}) x

Graph

Beliebte Beispiele

y^{'''}-2y^'=2,y^{''}(0)=-1

y^{^{'''}} - 2 y^{^{'}} = 2, y^{^{''}} (0) = - 1

y^{''}+4y=sin(x)*sin(2x)

y^{^{''}} + 4 y = sin (x) \cdot sin (2 x)

y^{''}+y^'=cos(x),y(0)=0,y^'(0)=1

y^{^{''}} + y^{^{'}} = cos (x), y (0) = 0, y^{^{'}} (0) = 1

4y^{''}-y=e^{(x/2)}+5

4 y^{^{''}} - y = e^{(\frac{x}{2})} + 5

x^{''}+64x=sin(5t)

x^{^{''}} + 64 x = sin (5 t)