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Beliebt Rechnen >

y^{''}+3y+2=0,y(2)=-1,y^'(0)=0

Lösung

y^{^{''}} + 3 y + 2 = 0, y (2) = - 1, y^{^{'}} (0) = 0

Lösung

y = - \frac{cos ( 3 t )}{3 cos ( 2 3 )} - \frac{2}{3}

Schritte zur Lösung

y^{''} (t) + 3 y + 2 = 0

Solve linear ODE:

y = - \frac{cos ( 3 t )}{3 cos ( 2 3 )} - \frac{2}{3}

y = - \frac{cos ( 3 t )}{3 cos ( 2 3 )} - \frac{2}{3}

Beliebte Beispiele

y^{''}-2y^'+2y=e-t,y(0)=0,y^'(0)=1

y^{^{''}} - 2 y^{^{'}} + 2 y = e - t, y (0) = 0, y^{^{'}} (0) = 1

y^{''}-2y-3y=-3xe^{-x}

y^{^{''}} - 2 y - 3 y = - 3 x e^{- x}

y^{''}+6y^'+8y=t\H(t-3)

y^{^{''}} + 6 y^{^{'}} + 8 y = t H (t - 3)

1/2 y^{''}+2y=4tan(2t)-1/3 e^{2t}

\frac{1}{2} y^{^{''}} + 2 y = 4 tan (2 t) - \frac{1}{3} e^{2 t}

x^{''}+16x=102e^{-2t}cos(4t)

x^{^{''}} + 16 x = 102 e^{- 2 t} cos (4 t)