y^{''}+9y=0,y(0)=3,y^'(0)=-4

Lösung

y^{^{''}} + 9 y = 0, y (0) = 3, y^{^{'}} (0) = - 4

y = 3 cos (3 t) - \frac{4}{3} sin (3 t)

Schritte zur Lösung

y^{''} (t) + 9 y = 0

Solve linear ODE:

y = 3 cos (3 t) - \frac{4}{3} sin (3 t)

y = 3 cos (3 t) - \frac{4}{3} sin (3 t)

y^{^{''}} - 6 y^{^{'}} + 25 y = 0, y (0) = 2, y^{^{'}} (0) = 2

y^{^{''}} = 5 y, y (0) = - 2, y (2) = 10

y^{^{''}} - 8 y^{^{'}} + 32 y = 0, y (0) = 5, y^{^{'}} (0) = - 4

y^{^{''}} + 3 y^{^{'}} + 5 y = 0, y (0) = 0, y^{^{'}} (0) = 1

x^{^{''}} + 64 x = 0, x (0) = \frac{4}{12}, x^{^{'}} (0) = 0