y^{''}-y^'+56y=0

Lösung

y^{^{''}} - y^{^{'}} + 56 y = 0

y = e^{\frac{t}{2}} (c_{1} cos (\frac{223 t}{2}) + c_{2} sin (\frac{223 t}{2}))

Schritte zur Lösung

y^{''} (t) - y^{'} (t) + 56 y = 0

Solve linear ODE:

y = e^{\frac{t}{2}} (c_{1} cos (\frac{223 t}{2}) + c_{2} sin (\frac{223 t}{2}))

y = e^{\frac{t}{2}} (c_{1} cos (\frac{223 t}{2}) + c_{2} sin (\frac{223 t}{2}))

y^{^{''}} + 2 y^{^{'}} - y = 0, y (0) = x e^{- x}

y^{^{'''}} + y^{^{'}} + 2 y = 0

y^{^{''}} = \frac{- y ^{^{'}} - 5 y}{4}

f^{^{''}} (x) = - f (x)

\frac{d ^{2} y}{d x ^{2}} - 2 \frac{d y}{d x} - 3 y = 0