x^{''}+0.5x^'+17/16x=0

Lösung

x^{^{''}} + 0.5 \cdot x^{^{'}} + \frac{17}{16} \cdot x = 0

x = e^{- 0.25 t} (c_{1} cos (t) + c_{2} sin (t))

Schritte zur Lösung

x^{''} (t) + 0.5 \cdot x^{'} (t) + \frac{17}{16} \cdot x = 0

Solve linear ODE:

x = e^{- 0.25 t} (c_{1} cos (t) + c_{2} sin (t))

x = e^{- 0.25 t} (c_{1} cos (t) + c_{2} sin (t))

4 y^{^{''}} + 12 y^{^{'}} + 9 y = 0, y (0) = 1, y^{^{'}} (0) = - 4

y^{^{''}} + 4 y^{^{'}} + 7 y = 0, y (0) = 1, y^{^{'}} (0) = - 2

y^{^{''}} - 7 y^{^{'}} - 8 y = 0, y (0) = 2, y^{^{'}} (0) = 7

y^{^{''}} - y^{^{'}} = - y

4 y^{^{''}} - 36 y^{^{'}} + 81 y = 0