What is the derivative of x^4-2x^2-8 ?

The derivative of x^4-2x^2-8 is 4x^3-4x

What is the first derivative of x^4-2x^2-8 ?

The first derivative of x^4-2x^2-8 is 4x^3-4x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

\frac{d}{d x} (x^{4} - 2 x^{2} - 8)

4 x^{3} - 4 x

Solution steps

\frac{d}{d x} (x^{4} - 2 x^{2} - 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) - \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (8)

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (8) = 0

= 4 x^{3} - 4 x - 0

Simplify

= 4 x^{3} - 4 x

What is the derivative of x^4-2x^2-8 ?
The derivative of x^4-2x^2-8 is 4x^3-4x
What is the first derivative of x^4-2x^2-8 ?
The first derivative of x^4-2x^2-8 is 4x^3-4x