5y^{''}+45y=0,y(0)=-8,y^'(0)=0

Lösung

5 y^{^{''}} + 45 y = 0, y (0) = - 8, y^{^{'}} (0) = 0

y = - 8 cos (3 t)

Schritte zur Lösung

5 y^{''} (t) + 45 y = 0

Solve linear ODE:

y = - 8 cos (3 t)

y = - 8 cos (3 t)

4 y^{^{''}} + \frac{16}{0.25} y = 0, y (0) = 0

y^{^{''}} + 3 y^{^{'}} - 4 y = 0, y (0) = 3, y^{^{'}} (0) = 2

y^{^{''}} + 10 y^{^{'}} + 21 y = 0, y (0) = 1, y^{^{'}} (0) = 0

y^{^{''}} + y^{^{'}} + 9.25 y = 0, y^{^{'}} (0) = 8

\frac{d ^{2} x}{d t ^{2}} + 4 \frac{d x}{d t} + 5 x = 0, x (0) = 1