y^{''}+49y=0,y(0)=2,y^'(0)=1

Lösung

y^{^{''}} + 49 y = 0, y (0) = 2, y^{^{'}} (0) = 1

y = 2 cos (7 t) + \frac{1}{7} sin (7 t)

Schritte zur Lösung

y^{''} (t) + 49 y = 0

Solve linear ODE:

y = 2 cos (7 t) + \frac{1}{7} sin (7 t)

y = 2 cos (7 t) + \frac{1}{7} sin (7 t)

y^{^{''}} - 4 y + 3 y = 0, y (0) = - 1, y^{^{'}} (0) = - 5

y^{^{''}} + 4 y^{^{'}} + 20 y = 0, y (0) = 6, y^{^{'}} (0) = - 11

4 y^{^{''}} + 9 y = 0, y (0) = 0, y^{^{'}} (0) = 1

y^{^{'''}} - 7 y^{^{''}} + 25 y^{^{'}} - 39 y = 0

y^{^{''}} - 4 y^{^{'}} + 3 y = 0, y (0) = 0, y^{^{'}} (0) = 1