y^{'''}-12y^{''}-28y^'+480y=0

Lösung

y^{^{'''}} - 12 y^{^{''}} - 28 y^{^{'}} + 480 y = 0

y = c_{1} e^{- 6 t} + c_{2} e^{8 t} + c_{3} e^{10 t}

Schritte zur Lösung

y^{'''} (t) - 12 y^{''} (t) - 28 y^{'} (t) + 480 y = 0

Solve linear ODE:

y = c_{1} e^{- 6 t} + c_{2} e^{8 t} + c_{3} e^{10 t}

y = c_{1} e^{- 6 t} + c_{2} e^{8 t} + c_{3} e^{10 t}