y^{''}-1y^'+0.1y=0

Lösung

y^{^{''}} - 1 y^{^{'}} + 0.1 y = 0

y = c_{1} e^{\frac{( 5 + 15 ) t}{10}} + c_{2} e^{\frac{( 5 - 15 ) t}{10}}

Schritte zur Lösung

y^{''} (t) - 1 y^{'} (t) + 0.1 y = 0

Solve linear ODE:

y = c_{1} e^{\frac{( 5 + 15 ) t}{10}} + c_{2} e^{\frac{( 5 - 15 ) t}{10}}

y = c_{1} e^{\frac{( 5 + 15 ) t}{10}} + c_{2} e^{\frac{( 5 - 15 ) t}{10}}