What is the solution for y^{''}-5y+6y=0,y(0)=-3/5 ,y^'(0)=-13/5 ?

The solution for y^{''}-5y+6y=0,y(0)=-3/5 ,y^'(0)=-13/5 is y=-3/5 cos(t)-13/5 sin(t)

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y^{''}-5y+6y=0,y(0)=-3/5 ,y^'(0)=-13/5

y^{^{''}} - 5 y + 6 y = 0, y (0) = - \frac{3}{5}, y^{^{'}} (0) = - \frac{13}{5}

y = - \frac{3}{5} cos (t) - \frac{13}{5} sin (t)

Solution steps

y^{''} (t) - 5 y + 6 y = 0

Solve linear ODE:

y = - \frac{3}{5} cos (t) - \frac{13}{5} sin (t)

y = - \frac{3}{5} cos (t) - \frac{13}{5} sin (t)

What is the solution for y^{''}-5y+6y=0,y(0)=-3/5 ,y^'(0)=-13/5 ?
The solution for y^{''}-5y+6y=0,y(0)=-3/5 ,y^'(0)=-13/5 is y=-3/5 cos(t)-13/5 sin(t)