60x^{''}+240x=0

Lösung

60 x^{^{''}} + 240 x = 0

x = c_{1} cos (2 t) + c_{2} sin (2 t)

Schritte zur Lösung

60 x^{''} (t) + 240 x = 0

Solve linear ODE:

x = c_{1} cos (2 t) + c_{2} sin (2 t)

x = c_{1} cos (2 t) + c_{2} sin (2 t)

y^{^{''}} + (\frac{1}{2}) y = 0

y^{^{'''}} + y^{^{''}} = 0, y^{^{'}} (0) = 0, y^{^{''}} (0) = 0

y^{^{''}} + 10 y^{^{'}} + 25 y = 0, y (0) = 8, y^{^{'}} (0) = 7

y^{^{''}} - 6 y^{^{'}} - 7 y = 0, y (0) = 4, y^{^{'}} (0) = 4

y^{^{''}} - 6 y^{^{'}} + 25 y = 0, y (0) = 2, y^{^{'}} (0) = - 2