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Beliebt Rechnen >

y^{''}+8y^'+41y=0,y^'(0)=2,y(0)=1

Lösung

y^{^{''}} + 8 y^{^{'}} + 41 y = 0, y^{^{'}} (0) = 2, y (0) = 1

Lösung

y = e^{- 4 t} (cos (5 t) + \frac{6}{5} sin (5 t))

Schritte zur Lösung

y^{''} (t) + 8 y^{'} (t) + 41 y = 0

Solve linear ODE:

y = e^{- 4 t} (cos (5 t) + \frac{6}{5} sin (5 t))

y = e^{- 4 t} (cos (5 t) + \frac{6}{5} sin (5 t))

Graph

Beliebte Beispiele

2y^{''}-17y^'-9y=0,y(0)=4,y^'(0)=-7

2 y^{^{''}} - 17 y^{^{'}} - 9 y = 0, y (0) = 4, y^{^{'}} (0) = - 7

y^{''}+2y^'+y=0,y(0)=1,y^'(0)=-2

y^{^{''}} + 2 y^{^{'}} + y = 0, y (0) = 1, y^{^{'}} (0) = - 2

u^{^{''}} = H (t)

0.25*0.04x^{''}+2*0.04x^'+x=0

0.25 \cdot 0.04 x^{^{''}} + 2 \cdot 0.04 x^{^{'}} + x = 0

y^{''}+20y^'+92y=0

y^{^{''}} + 20 y^{^{'}} + 92 y = 0