33y^{''''}+23y^{''}+4y=0

Lösung

33 y^{^{''''}} + 23 y^{^{''}} + 4 y = 0

y = c_{1} cos (\frac{t}{3}) + c_{2} sin (\frac{t}{3}) + c_{3} cos (\frac{2 t}{11}) + c_{4} sin (\frac{2 t}{11})

Schritte zur Lösung

33 y^{(4)} (t) + 23 y^{''} (t) + 4 y = 0

Solve linear ODE:

y = c_{1} cos (\frac{t}{3}) + c_{2} sin (\frac{t}{3}) + c_{3} cos (\frac{2 t}{11}) + c_{4} sin (\frac{2 t}{11})

y = c_{1} cos (\frac{t}{3}) + c_{2} sin (\frac{t}{3}) + c_{3} cos (\frac{2 t}{11}) + c_{4} sin (\frac{2 t}{11})

y^{^{''''}} - 5 y^{^{'''}} + 6 y^{^{''}} + 4 y^{^{'}} - 8 y = 0

y^{^{''}} - 10 y^{^{'}} + 25 y = 0, y (0) = - 3, y^{^{'}} (0) = - \frac{68}{5}

y^{^{''}} + y^{^{'}} + y 2 = 0

49 y^{^{''}} - 70 y^{^{'}} + 25 y = 0

l in e a r y^{^{'''}} + 7 y^{^{''}} + 8 y^{^{'}} - 16 y = 0