2y^{''}+10y^'-12y=0

Lösung

2 y^{^{''}} + 10 y^{^{'}} - 12 y = 0

y = c_{1} e^{t} + c_{2} e^{- 6 t}

Schritte zur Lösung

2 y^{''} (t) + 10 y^{'} (t) - 12 y = 0

Solve linear ODE:

y = c_{1} e^{t} + c_{2} e^{- 6 t}

y = c_{1} e^{t} + c_{2} e^{- 6 t}

4 y^{^{'''}} - 11 y^{^{''}} - 19 y^{^{'}} - 4 y = 0

y^{^{''}} - 3 y^{^{'}} = 0, y (0) = 7 - 7 e^{3}, y (1) = 0

y^{^{''}} + 3 y^{^{'}} - 10 y = 0, y (0) = 1, y^{^{'}} (0) = 30

y^{^{''}} - 20 y^{^{'}} + 101 y = 0, y (0) = 8, y^{^{'}} (0) = 1

r^{2} y^{^{''}} + r y^{^{'}} - n^{2} y = 0